6w^2+5w-14=0

Solution for 6w^2+5w-14=0 equation:

6w^2+5w-14=0

a = 6; b = 5; c = -14;
Δ = b2-4ac
Δ = 52-4·6·(-14)
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-19}{2*6}=\frac{-24}{12}
=-2
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+19}{2*6}=\frac{14}{12}
=1+1/6
$